Power gurus

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ELit3

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0.045300 cents per kwh in a month of running 5amps / 120v how would I determine how many kwh I've used? I'm trying to determine my monthly power bill.
 

Blinky 42

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Aug 6, 2015
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If your actual current draw is 5A @ 120V over 1 hour:
5A * 120V * 1h = 600Watt Hr = 0.6 kWhr used over the 1hour.
14.4kWh / day, ~432kWh per month assuming 30 days
 
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T_Minus

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First example on google actually had your #s ;)
Calculate Watts

But basically you just multiply them for most loads :) to get watts from amps & voltage.

Then * each hour it runs * days.

Then * your cost per kWh (0.0453)
 
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T_Minus

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And, for fun multiple my rate $0.28 kWh ;) for fun, and compare how great you have it, ha ha.
 
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ELit3

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5a x 120v = 600w
600w x 24h = 14,000w per day
14,000w p/d / 1,000 = $14.4 Per day if my math suites me
$14.4 per day x 30 days in a month = $432 per month

Correct?

Where do I add my billing kwh price?
 

Marsh

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May 12, 2013
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The new age way.
google "power usage calculator"

When I was in high school, no calculator in the classroom. Only slide rule.
 
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Marsh

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T_Minus did not tell you our top tier rate is $0.4 per KWH.

Last night, the SF bayarea was cool, I was mining with 25 machines, after I closed all the windows overnight.
This morning, my 2,500 sq ft house was warm and toasty .

This winter, instead of paying for natural gas , I'll be spending $0.4 KWH on mining.
 
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T_Minus

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@T_Minus holy hell how are you affording that.
Don't use a lot :) ha ha. It used to be .13 and then .18 is max we'd hit... I think now min. is .18 and next is .28 and you hit it almost guaranteed now the way they rate. Solar experiments are coming in the next few months, lol :)

T_Minus did not tell you our top tier rate is $0.4 per KWH.

Last night, the SF bayarea was cool, I was mining with 25 machines, after I closed all the windows overnight.
This morning, my 2,500 sq ft house was warm and toasty .

This winter, instead of paying for natural gas , I'll be spending $0.4 KWH on mining.
Argh, glad I haven't hit that usage / rate ;)

In winter our electric drops to ~$100-125/mo with the kids now, before the kids and slightly lower rates 70-80/mo was usual in winter.

It gets abit cooler where I'm at than Marsh (we get snow) so during winter cooling is a non-issue/cost... I haven't done the math or anything but I'd say you could almost 1/2 the server cooling power usage cost for summer to avg out for a year, so it's not THAT bad but still not cheap by any means, and requires more up front cost in fans / ducting to properly move the hot air, even in winter.
 
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ELit3

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T_Minus did not tell you our top tier rate is $0.4 per KWH.

Last night, the SF bayarea was cool, I was mining with 25 machines, after I closed all the windows overnight.
This morning, my 2,500 sq ft house was warm and toasty .

This winter, instead of paying for natural gas , I'll be spending $0.4 KWH on mining.
Don't use a lot :) ha ha. It used to be .13 and then .18 is max we'd hit... I think now min. is .18 and next is .28 and you hit it almost guaranteed now the way they rate. Solar experiments are coming in the next few months, lol :)



Argh, glad I haven't hit that usage / rate ;)

In winter our electric drops to ~$100-125/mo with the kids now, before the kids and slightly lower rates 70-80/mo was usual in winter.

It gets abit cooler where I'm at than Marsh (we get snow) so during winter cooling is a non-issue/cost... I haven't done the math or anything but I'd say you could almost 1/2 the server cooling power usage cost for summer to avg out for a year, so it's not THAT bad but still not cheap by any means, and requires more up front cost in fans / ducting to properly move the hot air, even in winter.
I have a few buddies who mine at my little spot because of the power cost I just charge them a $100 premium over the cost but its about time I figure out the exact cost instead of waiting for the power bill and distributing the cost.
 

StammesOpfer

Active Member
Mar 15, 2016
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Yup and the thing most people forget to calculate when looking at mining costs is the added heat load and the power used to remove that additional heat.
 

StammesOpfer

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Mar 15, 2016
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Yea I just add 1.7% or so on the cost to cover that.
It is significantly higher than that. Need to know the efficiency rating of you ac unit (or you could guess if it is old lets say 12 SEER new 17 SEER). Heat generated by 1 watt = 3.412142 BTU

So the math with your numbers.

5a x 120v = 600 watts
600w x 3.412142 = 2047 BTU
2047btu / 14 SEER = 146 watts (In addition to the original 600)
146w (from cooling) / 600w (Original draw) = 24.3%
$0.0453/kwh x 124.3% = $0.0563079/kwh (effective rate)
I like calculating the effective rate once and then just doing the math on the base load with the effective rate rather than doing the math to calculate BTU and A/C usage.

So it final calcs would be:
(600w [base load] + 146w [calculated cooling load]) / 1000 [to get Kilowatts] * 24 [hrs] * 30 [days] * 0.0453 [$/kwh] = $24.33
or
600w / 1000 * 24 * 30 * 0.0563079 [effective rate] = $24.33

These are theoretical numbers ignoring real world physics but they are pretty damn close.
 
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ELit3

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It is significantly higher than that. Need to know the efficiency rating of you ac unit (or you could guess if it is old lets say 12 SEER new 17 SEER). Heat generated by 1 watt = 3.412142 BTU

So the math with your numbers.

5a x 120v = 6,000 watts
6000w x 3.412142 = 20473 BTU
20473btu / SEER (I'll use 12) = 1706 watts (In addition to the original 6000)
1706w (from cooling) / 6000w (Original draw) = 28.4%
$0.0453/kwh x 128.4% = $0.0581652/kwh (effective rate)

These are theoretical numbers ignoring real world physics but they are pretty damn close.
I have a seer 14 right now.
 

T_Minus

Build. Break. Fix. Repeat
Feb 15, 2015
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It is significantly higher than that. Need to know the efficiency rating of you ac unit (or you could guess if it is old lets say 12 SEER new 17 SEER). Heat generated by 1 watt = 3.412142 BTU

So the math with your numbers.

5a x 120v = 6,000 watts
6000w x 3.412142 = 20473 BTU
20473btu / SEER (I'll use 12) = 1706 watts (In addition to the original 6000)
1706w (from cooling) / 6000w (Original draw) = 28.4%
$0.0453/kwh x 128.4% = $0.0581652/kwh (effective rate)

These are theoretical numbers ignoring real world physics but they are pretty damn close.
5 x 120 is not 6000 ;) =
 

StammesOpfer

Active Member
Mar 15, 2016
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5 x 120 is not 6000 ;) =
You are right accidentally added an extra 0 there and just ran with it. But for the rest of the math really doesn't matter cause it is all relative and still works out to the same percentage.

Edited to correct that and put it at 14 SEER for @ELit3
 
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